Asked By: Anonymous
I’ve got a underscore/backbone/require application and I would like to output all events that are triggered through backbone to the console (in other words: pass each event through console.log
function). I’ve tried wrapping it with underscore and manually replacing the function. Neither this:
console.log(Backbone.Events.trigger);
var trigger = Backbone.Events.trigger;
Backbone.Events.trigger = function(name) {
console.log('Event', name, 'triggered.');
trigger.apply(this, arguments);
}
nor this:
Backbone.Events.trigger = _.wrap(Backbone.Events.trigger, function(func) {
console.log('EVENT:', Array.prototype.slice.call(arguments));
func(Array.prototype.slice.call(arguments));
});
console.log(Backbone.Events.trigger);
worked. I’d appreciate a javascript (not coffeescript) solution.
Solution
Answered By: Anonymous
Your wrappings fail because Backbone mixes in Backbone.Events
behavior on Backbone.Model
, Backbone.Collection
, etc. For example, Backbone.Model
is defined as
var Model = Backbone.Model = function(attributes, options) {
...
};
_.extend(Model.prototype, Events, {
...
};
This means that when you redefine Backbone.Events.trigger
, it is already too late.
But all is not lost! You won’t be able to redefine all trigger
methods in one go, but you can redefine them on class level:
Backbone.Model.prototype.trigger = function() {
console.log('Event', arguments);
Backbone.Events.trigger.apply(this, arguments);
}
and a demo http://jsfiddle.net/nikoshr/G2Qfn/
For a given class, you can override the trigger method:
var M = Backbone.Model.extend({
trigger: function() {
console.log('Event', arguments);
Backbone.Model.prototype.trigger.apply(this, arguments);
}
});
http://jsfiddle.net/nikoshr/G2Qfn/1/
or for a given instance
var M = Backbone.Model.extend({});
var m = new M();
m.trigger = function() {
console.log('Event', arguments);
M.prototype.trigger.apply(this, arguments);
}